Skip to main content

C Programming Code To Create Pyramid and Pattern

C Programming Code To Create Pyramid and Pattern

Examples to print half pyramid, pyramid, inverted pyramid, Pascal's Triangle and Floyd's triangle in C Programming using control statements.
C programming pyramids
List of Source Code
Code to print triangles using *, digits and characters
Code to print inverted triangles using * and digits
Code to print full pyramids
Code to print Pascal's triangle
Code to print Floyd's triangle

Programs to print triangles using *, numbers and characters


Example 1: Program to print half pyramid using *

*
* *
* * *
* * * *
* * * * *
Source Code
#include <stdio.h>
int main()
{
    int i, j, rows;

    printf("Enter number of rows: ");
    scanf("%d",&rows);

    for(i=1; i<=rows; ++i)
    {
        for(j=1; j<=i; ++j)
        {
            printf("* ");
        }
        printf("\n");
    }
    return 0;
}

Example 2: Program to print half pyramid a using numbers

1
1 2
1 2 3
1 2 3 4
1 2 3 4 5
Source Code
#include <stdio.h>
int main()
{
    int i, j, rows;

    printf("Enter number of rows: ");
    scanf("%d",&rows);

    for(i=1; i<=rows; ++i)
    {
        for(j=1; j<=i; ++j)
        {
            printf("%d ",j);
        }
        printf("\n");
    }
    return 0;
}

Example 3: Program to print half pyramid using alphabets

A
B B
C C C
D D D D
E E E E E
Source Code
#include <stdio.h>
int main()
{
    int i, j;
    char input, alphabet = 'A';

    printf("Enter the uppercase character you want to print in last row: ");
    scanf("%c",&input);

    for(i=1; i <= (input-'A'+1); ++i)
    {
        for(j=1;j<=i;++j)
        {
            printf("%c", alphabet);
        }
        ++alphabet;

        printf("\n");
    }
    return 0;
}

Programs to print inverted half pyramid using * and numbers


Example 4: Inverted half pyramid using *

* * * * *
* * * *
* * * 
* *
*
Source Code
#include <stdio.h>
int main()
{
    int i, j, rows;

    printf("Enter number of rows: ");
    scanf("%d",&rows);

    for(i=rows; i>=1; --i)
    {
        for(j=1; j<=i; ++j)
        {
            printf("* ");
        }
        printf("\n");
    }
    
    return 0;
}

Example 5: Inverted half pyramid using numbers

1 2 3 4 5
1 2 3 4 
1 2 3
1 2
1
Source Code
#include <stdio.h>
int main()
{
    int i, j, rows;

    printf("Enter number of rows: ");
    scanf("%d",&rows);

    for(i=rows; i>=1; --i)
    {
        for(j=1; j<=i; ++j)
        {
            printf("%d ",j);
        }
        printf("\n");
    }

    return 0;
}

 Programs to display pyramid and inverted pyramid using * and digits


Example 6: Program to print full pyramid using *

        *
      * * *
    * * * * *
  * * * * * * *
* * * * * * * * *
Source Code
#include <stdio.h>
int main()
{
    int i, space, rows, k=0;

    printf("Enter number of rows: ");
    scanf("%d",&rows);

    for(i=1; i<=rows; ++i, k=0)
    {
        for(space=1; space<=rows-i; ++space)
        {
            printf("  ");
        }

        while(k != 2*i-1)
        {
            printf("* ");
            ++k;
        }

        printf("\n");
    }
    
    return 0;
}

Example 7: Program to print pyramid using numbers


        1
      2 3 2
    3 4 5 4 3
  4 5 6 7 6 5 4
5 6 7 8 9 8 7 6 5
Source Code
#include <stdio.h>
int main()
{
    int i, space, rows, k=0, count = 0, count1 = 0;

    printf("Enter number of rows: ");
    scanf("%d",&rows);

    for(i=1; i<=rows; ++i)
    {
        for(space=1; space <= rows-i; ++space)
        {
            printf("  ");
            ++count;
        }

        while(k != 2*i-1)
        {
            if (count <= rows-1)
            {
                printf("%d ", i+k);
                ++count;
            }
            else
            {
                ++count1;
                printf("%d ", (i+k-2*count1));
            }
            ++k;
        }
        count1 = count = k = 0;

        printf("\n");
    }
    return 0;
}

Example 8: Inverted full pyramid using *


* * * * * * * * *
  * * * * * * *
    * * * * *
      * * *
        *
Source Code
#include<stdio.h>
int main()
{
    int rows, i, j, space;

    printf("Enter number of rows: ");
    scanf("%d",&rows);

    for(i=rows; i>=1; --i)
    {
        for(space=0; space < rows-i; ++space)
            printf("  ");

        for(j=i; j <= 2*i-1; ++j)
            printf("* ");

        for(j=0; j < i-1; ++j)
            printf("* ");

        printf("\n");
    }

    return 0;
}

Example 9: Print Pascal's triangle


           1
         1   1
       1   2   1
     1   3   3    1
   1  4    6   4   1
 1  5   10   10  5   1 
Source Code
#include <stdio.h>
int main()
{
    int rows, coef = 1, space, i, j;

    printf("Enter number of rows: ");
    scanf("%d",&rows);

    for(i=0; i<rows; i++)
    {
        for(space=1; space <= rows-i; space++)
            printf("  ");

        for(j=0; j <= i; j++)
        {
            if (j==0 || i==0)
                coef = 1;
            else
                coef = coef*(i-j+1)/j;

            printf("%4d", coef);
        }
        printf("\n");
    }

    return 0;
}

Example 10: Print Floyd's Triangle.

1
2 3
4 5 6
7 8 9 10
Source Code
#include <stdio.h>
int main()
{
    int rows, i, j, number= 1;

    printf("Enter number of rows: ");
    scanf("%d",&rows);

    for(i=1; i <= rows; i++)
    {
        for(j=1; j <= i; ++j)
        {
            printf("%d ", number);
            ++number;
        }

        printf("\n");
    }

    return 0;
}

Comments

Popular posts from this blog

C Program to Find all Roots of a Quadratic Equation

C Program to Find all Roots of a Quadratic Equation This program accepts coefficients of a quadratic equation from the user and displays the roots (both real and complex roots depending upon the discriminant ).   To understand this example, you should have the knowledge of following C programming topics: C Programming Operators C if...else Statement The standard form of a quadratic equation is: ax 2 + bx + c = 0, where a, b and c are real numbers and a ≠ 0 The term b 2 -4ac is known as the discriminant of a quadratic equation. The discriminant tells the nature of the roots. If discriminant is greater than 0, the roots are real and different. If discriminant is equal to 0, the roots are real and equal. If discriminant is less than 0, the roots are complex and different. Example: Program to Find Roots of a Quadratic Equation #include <stdio.h> #include <math.h> int main () ...

C Program to Find ASCII Value of a Character

C Program to Find ASCII Value of a Character In C programming, a character variable holds ASCII value (an integer number between 0 an 127) rather than character itself. You will learn how to find ASCII value of a character in this program.   To understand this example, you should have the knowledge of following C programming topics: C Programming Data Types C Programming Constants and Variables C Input Output (I/O) A character variable holds ASCII value (an integer number between 0 and 127) rather than that character itself in C programming. That value is known as ASCII value. For example , ASCII value of 'A' is 65. What this means is that, if you assign 'A' to a character variable, 65 is stored in that variable rather than 'A' itself. Program to Print ASCII Value #include <stdio.h> int main () { char c ; printf ( "Enter a character: " ); // Re...

C Program to Demonstrate the Working of Keyword long

C Program to Demonstrate the Working of Keyword long The long is a size modifier, indicated by keyword long, that may increase the size of a variable during declaration. This program will demonstrate the working of long keyword.   To understand this example, you should have the knowledge of following C programming topics: C Programming Data Types C Programming Constants and Variables C Input Output (I/O) Example: Program to Demonstrate the Working of long #include <stdio.h> int main () { int a ; long b ; long long c ; double e ; long double f ; printf ( "Size of int = %ld bytes \n" , sizeof ( a )); printf ( "Size of long = %ld bytes\n" , sizeof ( b )); printf ( "Size of long long = %ld bytes\n" , sizeof ( c )); printf ( "Size of double = %ld bytes\n" , sizeof ( e )); printf ( "Size of long doub...